How much D-glucose is in a 2-μL aliquot of a solution with a concentration of 72 g/L?

How much D-glucose is in a 2-μL aliquot of a solution with a concentration of 72 g/L?

• A. 3.6 × 10-7 g
• B. 1.4 × 10-4 g
• C. 3.6 × 10-4 g
• D. 1.4 × 10-1 g

Answer: (B)

To find the amount of D-glucose in a 2-μL aliquot of a solution with a concentration of 72 g/L, we start by converting the volume from microliters to liters because the concentration is given in grams per liter (g/L). 1. **Convert Volume**: - 2 μL = 2 × 10^-6 L 2. **Calculate the mass of D-glucose**: - Use the formula: \[ \text{mass} = \text{concentration} \times \text{volume} \] Substituting in the values, we have: \[ \text{mass} = 72 \, \text{g/L} \times 2 \times 10^{-6} \, \text{L} \] \[ \text{mass} = 72 \times 2 \times 10^{-6} \, \text{g} \] \[ \text{mass} = 144 \times 10^{-6} \, \text{g} \] \[ \text{mass} = 1.44

To find the amount of D-glucose in a 2-μL aliquot of a solution with a concentration of 72 g/L, we start by converting the volume from microliters to liters because the concentration is given in grams per liter (g/L).

1. Convert Volume:

• 2 μL = 2 × 10^-6 L

2. Calculate the mass of D-glucose:

• Use the formula:

[

\text{mass} = \text{concentration} \times \text{volume}

]

Substituting in the values, we have:

[

\text{mass} = 72 , \text{g/L} \times 2 \times 10^{-6} , \text{L}

]

[

\text{mass} = 72 \times 2 \times 10^{-6} , \text{g}

]

[

\text{mass} = 144 \times 10^{-6} , \text{g}

]

[

\text{mass} = 1.44