What is the required power to keep a railcar moving at 40 m/s if the force applied is 1000 N?

Study for the AAMC Chemical and Physical Foundations of Biological Systems Test. Study with flashcards and multiple choice questions, each question has hints and explanations. Get ready for your exam!

Multiple Choice

What is the required power to keep a railcar moving at 40 m/s if the force applied is 1000 N?

Explanation:
To determine the power required to keep the railcar moving at a constant speed, we can use the formula for power, which is the product of force and velocity. In this case, the power can be calculated using the equation: \[ \text{Power} = \text{Force} \times \text{Velocity} \] Given that the force applied to the railcar is 1000 N and the velocity is 40 m/s, the calculation would be: \[ \text{Power} = 1000 \, \text{N} \times 40 \, \text{m/s} = 40000 \, \text{W} \] Since 1 kW is equivalent to 1000 W, we can convert 40000 W into kilowatts: \[ 40000 \, \text{W} = 40 \, \text{kW} \] Thus, the required power to maintain the railcar's speed of 40 m/s, given a force of 1000 N, is indeed 40 kW. This calculation reflects the relationship between force and velocity in achieving a specific power output in mechanical systems.

To determine the power required to keep the railcar moving at a constant speed, we can use the formula for power, which is the product of force and velocity. In this case, the power can be calculated using the equation:

[ \text{Power} = \text{Force} \times \text{Velocity} ]

Given that the force applied to the railcar is 1000 N and the velocity is 40 m/s, the calculation would be:

[ \text{Power} = 1000 , \text{N} \times 40 , \text{m/s} = 40000 , \text{W} ]

Since 1 kW is equivalent to 1000 W, we can convert 40000 W into kilowatts:

[ 40000 , \text{W} = 40 , \text{kW} ]

Thus, the required power to maintain the railcar's speed of 40 m/s, given a force of 1000 N, is indeed 40 kW. This calculation reflects the relationship between force and velocity in achieving a specific power output in mechanical systems.

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